(Sin 270 . Cos 135 - Tan 135)/(Sin 150 . Cos 225) = [(-1) . (-1/2√2) - (-1)]/[1/2 . (-1/2√2)] = [1/2√2 + 1]/[-1/4√2] = [(√2 + 2)/2]/[-1/4√2] = -(2 + 2√2) = -2 -
Matematika
maxandra
Pertanyaan
(Sin 270 . Cos 135 - Tan 135)/(Sin 150 . Cos 225)
= [(-1) . (-1/2√2) - (-1)]/[1/2 . (-1/2√2)]
= [1/2√2 + 1]/[-1/4√2]
= [(√2 + 2)/2]/[-1/4√2]
= -(2 + 2√2)
= -2 - 2√2
tolong lebih rincikan mksdnya cara hitungnya ko bisa dpt ini
= [(-1) . (-1/2√2) - (-1)]/[1/2 . (-1/2√2)]
= [1/2√2 + 1]/[-1/4√2]
= [(√2 + 2)/2]/[-1/4√2]
= -(2 + 2√2)
= -2 - 2√2
tolong lebih rincikan mksdnya cara hitungnya ko bisa dpt ini
1 Jawaban
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1. Jawaban whongaliem
(sin 270° . cos 135° - tan 135°) / (sin 150° . cos 225°)
= sin 270° . cos (90 + 45)° - tan (90 + 45°) / {sin (90 + 60)° .cos (180 + 45)°
= {sin 270° - sin 45° - (- cot 45°)} / ( cos 60° . - sin 45°)
= (- sin 270° .sin 45° + cot 45° ) / - (cos 60° . sin 45°)
= { - (- 1) (1/2√2) + 1} / {- (1/2) (1/2 √2)
= (1/2 √2 + 1) / (-1/4 √2) ....... kalikan dengan 4/4
= (2√2 + 4) / - √2 ........ kalikan dengan √2 / √2
= (4 + 4√2) / - 2
= - 2 - 2√2