Bila x1 & x2 adl harga x yg memenuhi persamaan 5logkuadratx - 5logx - 20=0 nilai x1.x2 adalah
Matematika
Luthfisyarif14
Pertanyaan
Bila x1 & x2 adl harga x yg memenuhi persamaan 5logkuadratx - 5logx - 20=0 nilai x1.x2 adalah
2 Jawaban
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1. Jawaban keruasriki
langsung aja ya
5logx1 + 5logx2 = -b/a = -(-1)/1 = 1
5log(x1.x2) = 1
5log(x1.x2) = 5log5^1
x1.x2 = 5^2
x1.x2 = 5 -
2. Jawaban arsetpopeye
5log^2 x - 5logx - 20 = 0
(5logx)^2 - 5logx - 20 = 0
Misal 5logx = a
a^2 - a - 20 = 0
(a - 5)(a + 4) = 0
a = 5 atau a = -4
1) a = 5 => 5logx = 5log5^5 => x = 5^5
2) a = -4 => 5logx = 5log5^-4 => x = 5^-4
x1. x2 = 5^5 . 5^-4 = 5^1 = 5
^ = pangkat