Matematika

Pertanyaan

Bila x1 & x2 adl harga x yg memenuhi persamaan 5logkuadratx - 5logx - 20=0 nilai x1.x2 adalah

2 Jawaban

  • langsung aja ya

    5logx1 + 5logx2 = -b/a = -(-1)/1 = 1
    5log(x1.x2) = 1
    5log(x1.x2) = 5log5^1
    x1.x2 = 5^2
    x1.x2 = 5
  • 5log^2 x - 5logx - 20 = 0
    (5logx)^2 - 5logx - 20 = 0
    Misal 5logx = a
    a^2 - a - 20 = 0
    (a - 5)(a + 4) = 0
    a = 5 atau a = -4
    1) a = 5 => 5logx = 5log5^5 => x = 5^5
    2) a = -4 => 5logx = 5log5^-4 => x = 5^-4
    x1. x2 = 5^5 . 5^-4 = 5^1 = 5

    ^ = pangkat

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