Makasih Ya yang udah Jawab

<CEF=<AFG=3x+10
<BFG=<DEF=4x+30

Berarti
3x+10+4x+30=180°
3x+4x+10+30=180°
7x+40=180°
7x=140°
x=20°

Jadi <BFG
=4x+30
=4(20°)+30
=80°+30
=110°

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Bab Garis dan Sudut
Matematika SMP Kelas VII

∠CEF + ∠BFG = 180°
3x + 10° + 4x + 30° + 180°
7x = 180° - 40°
7x = 140°
x = 140° : 7
x = 20°

∠BFG = 4x + 30°
∠BFG = 4 . 20° + 30°
∠BFG = 110°

jawabannya C