Diketahui Fungsi f(x) = x – 3 dan g(x) = x² - 4x + 7, tentukanlah : a. (g ₀ ƒ) (x) b. (g ₀ ƒ) (1)

f (x) = x - 3
g (x) = x² - 4x + 7

gof (x)
= g (f (x))
= g (x - 3)
= (x - 3)² - 4x + 7
= (x² - 6x + 9) - 4 (x - 3) + 7
= x² - 6x + 9 - 4x + 12 + 7
= x² - 6x - 4x + 9 + 12 + 7
= x² - 10x + 28

gof (1)
= x² - 10x + 28
= (1)² - 10 (1) + 28
= 1 - 10 + 28
= -9 + 28
= 19

a. (g o f) (x) = [tex] (x - 3)^{2} - 4(x - 3) + 7 = x^{2} - 6x + 9 - 4x + 12 + 7 = x^{2} - 10x + 28[/tex]
b. ( g o f) (1) = [tex] (1 - 3)^{2} - 4(1-3) + 7 = 1 + 9 - 4 + 12 + 7 = 25 [/tex]