Diketahui ƒ (x) = sin(4x2 + 3) tentukanlah a. ƒ’(x) b. ƒ”(x)

f(x)=sin(4x²+3)
f'(x)=(8x)cos(4x²+3)

cat: y=u.v
y'=u'v+uv'
f"(x)=8cos(4x²+3)-(8x)(8x)sin(4x²+3)
=8cos(4x²+3)-64x²(sin(4x²+3))