Perbandingan rusuk balok adalah 2 : 3 : 5. Volume balok 1.920cm³. Berapa seluruh luas permukaan balok?
Matematika
lnf27
Pertanyaan
Perbandingan rusuk balok adalah 2 : 3 : 5. Volume balok 1.920cm³. Berapa seluruh luas permukaan balok?
2 Jawaban
-
1. Jawaban keruasriki
BALOK
misal
p : l : t = 2x : 3x : 5x
V = 1.920
p×l×t = 1.920
2x.3x.5x = 1.920
30x^3 = 1.920
x^3 = 1.920/30
x^3 = 64
x^3 = 4^3
x = 4 cm
p = 2x = 3×4 = 8 cm
l = 3x = 3×4 = 12 cm
t = 5x = 5×4 = 20 cm
Luas = 2×(pl + pt + lt)
Luas = 2×(8(12) + 8(20) + 12(20))
Luas = 2×(96 + 160 + 240)
Luas = 2×(496)
Luas = 992 cm^2 -
2. Jawaban LOVEJOY
2x × 3x × 5x = 1920 cm³
30x³ = 1920 cm³
x³ = 1920 cm³/30
x³ = 64 cm
x = ∛64 cm
x = 4 cm
L = (2 × a × b) + (2 × b × c ) + (2 × a × c)
= (2 × (2 × 4 cm) × (3 × 4 cm)) + (2 × (3 × 4 cm) × (5 × 4 cm)) + (2 × (2 × 4 cm) × (5 × 4 cm))
= (2 × 8 cm × 12 cm) + (2 × 12 cm × 20 cm) + (2 × 8 cm × 20 cm)
= 192 cm + 480 cm + 320 cm
= 992 cm²