Matematika

Pertanyaan

Perbandingan rusuk balok adalah 2 : 3 : 5. Volume balok 1.920cm³. Berapa seluruh luas permukaan balok?

2 Jawaban

  • BALOK

    misal
    p : l : t = 2x : 3x : 5x

    V = 1.920
    p×l×t = 1.920
    2x.3x.5x = 1.920
    30x^3 = 1.920
    x^3 = 1.920/30
    x^3 = 64
    x^3 = 4^3
    x = 4 cm

    p = 2x = 3×4 = 8 cm
    l = 3x = 3×4 = 12 cm
    t = 5x = 5×4 = 20 cm

    Luas = 2×(pl + pt + lt)
    Luas = 2×(8(12) + 8(20) + 12(20))
    Luas = 2×(96 + 160 + 240)
    Luas = 2×(496)
    Luas = 992 cm^2
  • 2x × 3x × 5x = 1920 cm³
    30x³ = 1920 cm³
    x³ = 1920 cm³/30
    x³ = 64 cm
    x = ∛64 cm
    x = 4 cm

    L = (2 × a × b) + (2 × b × c ) + (2 × a × c)
       = (2 × (2 × 4 cm) × (3 × 4 cm)) + (2 × (3 × 4 cm) × (5 × 4 cm)) + (2 × (2 × 4 cm) × (5 × 4 cm))
       = (2 × 8 cm × 12 cm) + (2 × 12 cm × 20 cm) + (2 × 8 cm × 20 cm)
       = 192 cm + 480 cm + 320 cm
       = 992 cm²

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