Matematika soal suku banyak (polinomial)

Suku Banyak

P(x) = x³ - x² - mx - 2m
P(x) : (x²-3x+2)  = h(x) + s(x)
p(x) : (x -2)(x-1) = h(x) + s(x)
x = 2
x = 1
misal  sisa  s(x)= mx  + n

sisa hasil bagi = nilai fungsi
s(x) =  P(x)
s(2) = p(2)
2m + n = (2)³ -(2)² -m(2)+ 2m
2m + n = 8 - 4 - 2m +2m
2m + n = 4 ..(1)
.
P(-1) = s(-1)
1-1+ m+2m = -m +n  --> 4m - n = 0 ....(1)

(1 dan 2)
2m + n = 4       
4m - n = 0
jumlahkan
6m = 4
m = 3/2
.
4m - n = 0--> 4(3/2) - n = -6
n = 0

P(x) = - x³ + x² - mx + 2m
P(x)  = -x³ + x² - 3/2 x + 3

p(n) = p(0) = 3