kak bntuin dong no 3a.& no 5 a,b. lamlirkan caranya ya..... #ini materi kls XI SMA# & no spam please#

limit

3a.
limi(x->1) (x² -1)(x-3) / (x² +x -2)
lim(x->1)  (x-1)(x+1)(x-3)/ (x-1)(x+2)
lim(x->1) (x+1)(x-3)/ (x+2)
x= 1
= (1+1)(1-3)/ (1+2)
= (2)(-2)/(3)
= - 4/3

5a.
lim(x->0) (2x³)(1 - cos x) / (sin³ 2x)(tan² x)
lim(x->0)  (2x³)/sin³ 2x  . (-2 sin² 1/2 x)/(tan² x)
= (2x)³/(2x)³ . -2(1/2 x)² /(x²)
= 1 (- 2(1/4))
= 1 (-1/2)
= - 1/2

5b
lim(x-> 0) (cos 5x - cos 9x)/(1 - cos 6x)
lim(x->0) - (cos 9x - cos 5x)/ (1- cos 6x)
lom(x->0) -{2 sin 7x. sin 2x) / (-2 sin² 3x)
= -2(7)(2)/(-2)(3)²
 = 14/9