tye certain value of water equilibrium constant (kw) at certain temperature and pressure is 2 × 10^14. the ph of 0,001 M Ba(OH)2 solution at the temperature is.

Gunakan cara biasa saja, tapi Kw diubah jadi 2 × 10^-14.

Ba(OH)2 adalah basa kuat yang DIASUMSIKAN terionisasi sempurna menurut reaksi:

Ba(OH)2(aq) --> Ba2+(aq) + 2 OH-(aq)
0.001 M

[OH-] = 2 × 0.001 = 2 × 10^-3 M

[H+] = Kw / [OH-]
[H+] = 2 × 10^-14 / (2 × 10^-3)
[H+] = 10^-11
pH = -log[H+] = 11