Diketahui layang layang ABCD dengan panjang AB:15cm dan diagonal BD:24cm jika keliling layang layang tersebut 70cm maka panjang diagonal AC adalah....

AO = √15² - 12²
AO = √225 - 144
AO = √81
AO = 9 cm

OC = √20² - 12²
OC = √400 - 144
OC = √256
OC = 16 cm

maka;
AC = OC + AO
AC = 16 cm + 9 cm
AC = 25 cm

✔ senang bisa membantu, semoga bermanfaat ya :)

Keliling = 70
2(AB + BC) = 70
AB + BC = 70/2
15 + BC = 35
BC = 20
Misal titik tengah BD = O sehingga
BO = OD = 1/2 (BD) = 1/2 (24) = 12
AO = √(AB^2 - BO^2) = √(15^2 - 12^2) = √(225 - 144) = √81 = 9
OC = √(BC^2 - BO^2) = √(20^2 - 12^2) = √(400 - 144) = √256 = 16
AC = AO + OC = 9 + 16 = 25 cm