jika panjang ad= 2√6, panjang bc = ... cm

AD/sin C = CD/sin A
2akar6/sin 60 = CD/sin 30
CD = 2 akar 6 sin 30/sin 60
CD = akar 6 / sin 60 = 2akar2 cm

CD/sin B = BC/sin D
2akar2/ sin 45 = BC/sin 90
BC = 2akar2 / sin 45
BC = 4 cm

Tan 30° = CD/AD
√3/3 = CD/(2√6)
3CD = 2√18
3CD = 2 . 3√2
CD = 2√2

Sin 45° = CD/BC
√2/2 = (2√2)/BC
√2 BC = 4√2
BC = 4 cm