Matematika

Pertanyaan

tolong sama caranya ya, jangan jawab asal asalan plisss..
tolong sama caranya ya, jangan jawab asal asalan plisss..

1 Jawaban

  • sin 60= 1/2√3
    cos 60 = 1/2
    tan (-60) = - tan 60 = - √3
    tan 45 = 1
    sin 30 = 1/2
    sin 45 = 1/2 √2
    sub ke soal

    {(sin² 60 - cos² 60+ tan(-60)} / (tan 45 + sin 30) sin 45 =
    = {(1/2 √3)² -(1/2)² - √3)} / (1 + 1/2)(1/2 √2)
    =(3/4  - 1/4 - √3) / (3/2)(1/2 √2)
    = (1/2 - √3) / (3/4) √2
    = 4(1/2 - √3)/ (3√2)
    = (2 - 4√3)(√2)/ 3)
    = 2(1 - 2√3).√2 / 3)
    = (2√2)/(3). {(1 - 2√3)}