tolong bantu jawab pakek cara iya

misalkan : y = f(x)
a) y = [(akar x^2) + 2] / [2x + 1]
y × [2x + 1] = [x + 2]
2xy + y = x + 2
2xy - x = 2 - y
x ×[2y - 1] = 2 - y
x = [2 - y] / [2y - 1]
f^(-1)(x) = [2 - x] / [2x - 1] , x =/= 1/2

b) f(x) = 6/[(akar x^4) - 1]
y = 6/[(akar x^4) - 1]
y = 6/ [x^2 - 1]
y × [x^2 - 1] = 6
x^2y - y = 6
x^2y = 6 + y
x^2 = [6 + y] / y
x = akar [(6 + y) / y]
f^(-1)(x) = akar [(6 + x) / x] , x =/= 0
c) f(x) = akar 9x^2 + akar 64
y = akar 9x^2 + akar 64
y = 3x + 8
3x = y - 8
x = (y - 8) / 3
f^('1)(x) = (x - 8) / 3