Jika titik a=(-1,3,1), b(m,5,n),dan c(-7,7,3) segaris maka ab:bc adalah

TITIK SEGARIS (KOLINEAR)

ab = kbc
b - a = k(c - b)
(m, 5, n) - (-1, 3, 1) = k((-7, 7, 3) - (m, 5, n))
(m+1, 2, n-1) = k(-7-m, 2, 3-n)
(m+1, 2, n-1) = (k(-7-m), 2k, k(3-n))

2 = 2k
k = 2/2
k = 1

m+1 = k(-7-m)
m+1 =1(-7-m)
m+1 = -7-m
m+m = -7-1
2m = -8
m = -8/2
m = -4

n-1 = k(3-n)
n-1 = 1(3-n)
n-1 = 3-n
n+n = 3+1
2n = 4
n = 4/2
n = 2

sehingga
a (-1,3,1)
b (-4, 5, 2)
c (-7, 7, 3)

ab : bc
=> (-4-(-1))/(-7-(-4))
=> (-4+1)/(-7+4)
=> -3/-3
=> 1/1
=> 1 : 1

atau

=> (5-3)/(7-5)
=> 2/2
=> 1/1
=> 1 : 1 ( sebenarnya ini tanpa harus mencari nilai m dan n ) hehehe