Prisma Abcd.Efgh . jarak dari titik D ke garis TH adalah

DB=√AD^2 + AB^2
= √36+36
=√72 = 6√2
DT = 3√2
TH= √DH^2+DT^2
TH = √8^2 + (3√2)^2
TH = √64 + 18
TH= √82 = 2√41

DH = 8
DB = √(6^2 + 6^2) = √(36 + 36) = √72 = 6√2
DT = 1/2 DB = 1/2 (6√2) = 3√2
HT = √(8^2 + (3√2)^2) = √(64 + 18) = √82
Jarak D ke HT = (DH . DT)/HT
= (8 . 3√2) / √82
= (8 . 3) / √41
= 24/√41 . √41/√41
= (24/41) √41 cm