jika f(x)=3X^2-2ax+7 dan f'(1)=0, maka f'(2)=... A.1 B.2 C. 4 D.6 E.8

DIFFERENSIAL

f'(x) = 6x - 2a
6x - 2a = f'(x)
6(1) - 2a = f'(1)
6 - 2a = 0
-2a = -6
a = -6/-2
a = 3

sehingga
f'(x) = 6x - 2(3)
f'(x) = 6x - 6

jadi
f'(2) = 6×2 - 6
f'(2) = 12 - 6
f'(2) = 6

f(x) = 3x² - 2ax + 7
f'(x) = 2 . 3 x - 1 . 2a 
f'(x) = 6x - 2a 
f'(1) = 0
6 - 2a = 0
-2a = -6
a = 3

f'(x) = 6x - 2 . 3
f'(x) = 6x - 6
f'(2) = 6 . 2 - 6
= 12 - 6
= 6

maka f'(2) = 6

jawaban di pilihan D