Di jawab no 7 saja gan Pake cara mengenai balok :)

Cari AB dulu pake Phytagoras antara p dan l

AB = √p^2 + l^2
AB = √12^2 + 8^2
AB = √144 + 64
AB = √208 --> √(16×13)= 4√13 cm.


Mencari luas bidang BDHF

BDHF = AB x BF (BF = t)
BDHF = 4√13 x 4
BDHF = 16√13 cm2 (D)

Bab Bangun Ruang
Matematika SMP Kelas VIII

balok
diagonal alas = √(12² + 8²)
diagonal alas = √(144 + 64)
diagonal alas = √208
diagonal alas = 4√13 cm

luas bidang diagonal BDHE
= diagonal alas x tinggi
= 4√13 x 4
= 16√13 cm²

◎◎ D ◎◎