dalam larutan nh4oh 0,1 m (kb nh oh=10^-5) banyaknya h+ adalah.. jelaskan
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Pertanyaan
dalam larutan nh4oh 0,1 m (kb nh oh=10^-5) banyaknya h+ adalah..
jelaskan
jelaskan
1 Jawaban
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1. Jawaban Robinn
NH4OH â NH4+ + OH-
[OH-] = âKb . M
[OH-] = â10^-5 . 10^-1
[OH-] = â10^-6
[OH-] = 10^-3
pOH = -log[OH-]
pOH = -log10^-3
pOH = 3
pH = 14 - pOH
pH = 14 - 3
pH = 11
pH = -log[H+]
[H+] = 10^-11