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Pertanyaan

dalam larutan nh4oh 0,1 m (kb nh oh=10^-5) banyaknya h+ adalah..
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1 Jawaban

  • NH4OH → NH4+ + OH-

    [OH-] = √Kb . M
    [OH-] = √10^-5 . 10^-1
    [OH-] = √10^-6
    [OH-] = 10^-3

    pOH = -log[OH-]
    pOH = -log10^-3
    pOH = 3

    pH = 14 - pOH
    pH = 14 - 3
    pH = 11

    pH = -log[H+]
    [H+] = 10^-11

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