no 20 besar
Matematika
steven359
Pertanyaan
no 20 besar <ABC adalah
A.4°
B.36°
C.54°
d.56°
A.4°
B.36°
C.54°
d.56°
2 Jawaban
-
1. Jawaban dnnyz07
Kedua sudut mmbntk 90 drjt (siku2)
15x - 6 + 8x +4 = 90
23x - 2 = 90
23x = 90 + 2
23x = 92
x = 92/23
x = 4 drjt
ABD = 15x - 6
= 15(4) - 6
= 60 - 6
= 54 drjt (C) -
2. Jawaban 18Navillera
90 = 15x - 6 + 8x + 4
23x = 92
x = 4
<ABD
= 15(4)-6
= 60 - 6
= 54°