2cos225°+4sin135°-tan315° =
Matematika
risma080596
Pertanyaan
2cos225°+4sin135°-tan315° =
1 Jawaban
-
1. Jawaban ariza10
cos 225°= -1/2√2
sin 135=1/2√2
tan 315=-1
maka:
=2 cos 225°+4sin135°-tan315°
=2(-1/2√2)+4(1/2√2) - (-1)
=-√2+2√2 + 1
= √2 + 1