Matematika

Pertanyaan

hasil dari sin(-45)°×cos(405)°/tan(-60)°

1 Jawaban

  • sin(-45) = - sin 45 = - 1/2√2
    cos 405 = cos (360 +45) = cos 45 = 1/2 √2
    tan (-60) = - tan 60 = - √3

    (sin(-45) . cos 405) /(tan(-60)) =
    = (-1/2 √2)(1/2 √2) / (-√3)
    = - (1/2) / (-√3)
    = 1/(2√3).....kalikan √3/√3
    =  1 (√3)/ (2√3)(√3)
    = 1/6 √3

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