hasil dari sin(-45)°×cos(405)°/tan(-60)°
Matematika
harmonisa1
Pertanyaan
hasil dari sin(-45)°×cos(405)°/tan(-60)°
1 Jawaban
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1. Jawaban DB45
sin(-45) = - sin 45 = - 1/2√2
cos 405 = cos (360 +45) = cos 45 = 1/2 √2
tan (-60) = - tan 60 = - √3
(sin(-45) . cos 405) /(tan(-60)) =
= (-1/2 √2)(1/2 √2) / (-√3)
= - (1/2) / (-√3)
= 1/(2√3).....kalikan √3/√3
= 1 (√3)/ (2√3)(√3)
= 1/6 √3