Tolog bantu jawab skarang ya

8. limit x→∞ [2x² + 2x - 6 ] / [ 6x -8 ]=  (2x²/x²)/(6x/x²) = 2/0 = ∞
9.limit x→1 [x² -6]  / [√(x²+3) + 3] = [(x²- 6) {√(x²+3) - 3}]/ [x²- 6]
limit x→1 √(x²+3) - 3 = √4 - 3 = 2-3 = - 1
10limit x→∞ [2x² +2x = 6] / [-2x²+3x+5] = (2x²)/(-2x²) = -1