larutan 100 ml nh3 0,1m direaksikan 400 ml hcl 0,025 m, maka ph larutan tersebut jika kb nh3 = 2x10-5
Kimia
alfikomariyah1625
Pertanyaan
larutan 100 ml nh3 0,1m direaksikan 400 ml hcl 0,025 m, maka ph larutan tersebut jika kb nh3 = 2x10-5
1 Jawaban
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1. Jawaban abbas13
n NH3=10
n hcl=10
[H]=√kw/kb×[G]
[H]=√10*-14/2×10*-5×10/500
[H]=✓5×10*-10×2×10*-2
[H]=√10. 10*-6
pH= - log ✓10. 10*-6
pH=6 -log✓10