persamaan garis yang melalui titik (2,-3) dan (-1,5)

misakan
x1 = 2 ; y1 = -3
x2 = -1 ; y2 = 5

(y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
(y - (-3))/(5-(-3)) = (x -2)/(-1-2)
(y + 3)/(5+3) = (x - 2)/(-3)
(y + 3)/8 = (x - 3)/(-3)
-3(y + 3) = 8(x - 3)
-3y - 9 = 8x - 24
8x + 3y - 24 + 9 = 0
8x + 3y - 15 = 0

(y2 - y1)/(x2 - x1) = (y - y1)/(x - x1)
(5 - (-3))/(-1 - 2) = (y - (-3))/(x - 2)
8/-3 = (y + 3)/(x - 2)
8x - 16 = -3y - 9
8x + 3y = 7
8x + 3y - 7 = 0