Tentukan fungsi invers : 1. g (x)=2x-1/6 2. h (x)=akar pangkat3 x+2

Nomer 1 sama 2 digabung
[tex]\displaystyle 1\\y=\frac{2x-1}{6} \\ 6y=2x-1 \\ 2x=6y+1 \\ x=\frac{6y+1}{2} \\ g^{-1}(x)=\frac{6x+1}{2} \\ \\ 2 \\ y=\sqrt[3]{x+2} \\ x+2=y^3 \\ x=y^3-2 \\ h^{-1}(x)=x^3-2[/tex]