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Pertanyaan

nilai limit x->-3 √-2x+3-3/x2+3x =.......... a) 1/6 b) 1/9 c) 1/18 d) - 1/27 e) - 1/18

1 Jawaban

  • Lim √-2x + 3 - 3 / x² + 3x
    x→-3

    Lim (√-2x + 3 - 3)(√-2x + 3 + 3)
    x→-3 .. / (x² + 3x)(√-2x + 3 + 3)

    Lim (-2x + 3 - 9)
    x→-3 .. / (x² + 3x)(√-2x + 3 + 3)

    Lim (-2x - 6)
    x→-3 .. / (x² + 3x)(√-2x + 3 + 3)

    Lim -2(x + 3)
    x→-3 .. / x(x + 3)(√-2x + 3 + 3)

    Lim -2 / x (√-2x + 3 + 3)
    x→-3

    = -2 / -3 (√-2(-3)+3 + 3)

    = -2 / -3 (√6+3 + 3)

    = -2 / -3 (√9 + 3)

    = -2 / -3 (3 + 3)

    = -2 / -3 (6)

    = 2 / 18

    = 1/9

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