Dadu putih dan biru digelindingkan sekali , berapakah peluang kejadian A.jumlah mata dadu lima B.jumlah mata dadu delapan

A. peluang jumlah mata dadu 5

A = {(1,4)(2,3)(3,2)(4,1)}
n(A) = 4
n(s) = 6×6 = 36

Peluang
= n(A)/n(s)
= 4/36
= 1/9

B. Peluang jumlah mata dadu 8

B = {(2,6)(3,5)(4,4)(5,3)(6,2)}
n(B) = 5
n(s) = 6² = 36

Peluang
= n(B)/n(s)
= 5/36


___________
#Semoga bermanfaat ^_^

ruang sampel
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)

maka peluang
A. 4/36 = 1/9

B. 5/36

✔ senang bisa membantu, semoga bermanfaat ya :)