jika y=x²+2x per x-3 maka y' = ...... pake cara ya☺

y = (x^2 + 2x)/(x - 3) = u/v
u = x^2 + 2x => u' = 2x + 2
v = x - 3 => v' = 1
y' = (u' v - v' u)/v^2
= ((2x + 2)(x - 3) - 1(x^2 + 2x)) / (x - 3)^2
= (2x^2 - 6x + 2x - 6 - x^2 - 2x) / (x - 3)^2
= (x^2 - 6x - 6) / (x - 3)^2

= (x^2 - 6x - 6) / (x^2 - 6x + 9)

^ = pangkat