Jika 2log a+ 2log b = 12 dan 3.2log a-2log g= 4,maka a+b = A.144 b.272 c.528 d.1.024 e.1.040

2 log a + 2 log b = 12
2 log (a.b) = 12
ab = [tex] 2^{12} [/tex] (I)

3. 2 log a - 2 log b = 4
    2 log [tex] a^{3} [/tex] - 2 log b= 4
    2 log [tex] \frac{a^{3} }{b} [/tex] = 4
    [tex] \frac{a^{3} }{b} [/tex] = [tex] 2^{4} [/tex]
    b = [tex] \frac{ a^{3} }{2^{4} } [/tex] (II)

(Substitusi ke I)
 
ab = [tex] 2^{12} [/tex]
a. [tex] \frac{ a^{3} }{2^{4} } [/tex] = [tex] 2^{12} [/tex]
[tex] \frac{ a^{4} }{2^{4} } = 2^{12} [/tex]
[tex] a^{4} = 2^{4}. 2^{12} [/tex]
[tex] a^{4} = 2^{16} [/tex]
a = [tex] 2^{4} [/tex] (III)

(Substitusi ke II)
[tex] \frac{ (2^{4})^{3} }{ 2^{4} } [/tex] = b
b = [tex] 2^{8} [/tex]

a + b = [tex] 2^{4} + 2^{8} = 16 + 256 = 272 [/tex]