Jika perbandongan panjang lebar dan tinggi suatu balok 5:4:2 .jika volume balok 2.560cm³ .hitunglah jumlah panjang rusuk balok tersebut @ tolong dijawab ya kak,

5x × 4x × 2x = 2.560 cm³
40x³ = 2.560 cm³
x² = 2.560/40
x² = 64 cm
x = √64
x = 8 cm

p = 5x
p = 5×8
p = 40 cm

l = 4x
l = 4×8
l = 32 cm

t = 2x
t = 2×8
t = 16 cm

p kawat= 4(p + l + t)
p kawat= 4(40 + 32 + 16)
p kawat= 4(90)
p kawat= 360 cm

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