40°R berapa °F, K, °C?

40°R = 9/4×40+32=122°F
40°R=5/4×40+273=323K
40°R=5/4×40=50°C

→Fahrenheit←
F = (9/4 R) + 32
F = (9/4 • 40) + 32
F = 90 + 32
F = 122°F

→Kelvin←
K = (5/4 R) + 273
K = (5/4 • 40) + 273
K = 50 + 273
K = 323 K

→Celcius←
C = 5/4 R
C = 5/4 • 40
C = 50°C