ada yang bisa menyelesaikan... ???

asimtot tegak : y = Lim (x => ~) f(x)
asimtot datar : x = Lim (y => ~) f(y)

f(x) = √(ax + 1) / (b - √(x + a))
Asimtot tegak : y = -2
Lim x => ~ {√(ax + 1)}/(b - √(x + a)) = -2
Lim x => ~ {√(ax/x + 1/x)} / (b/x^2 - √(x/x + a/x)) = -2
Lim x => ~ {√(a + 1/x)} / (b/x^2 - √(1 + a/x)) = -2
√(a + 0) / (0 - √(1 + 0)) = -2
√a / -1 = -2
√a = 2
a = 4

ax1 = 20 => 4x1 = 20 => x1 = 5

Asimtot datar : x = x1 = 5
Lim y => ~ f(y) = x1

f(x) = √(4x + 1) / (b - √(x + 4))
y akan mendekati tak hingga jika (b - √(x + 4)) = 0
b - √(x + 4) = 0
b = √(x + 4)
b = √(5 + 4)
b = √9 = 3

a + b = 4 + 3 = 7