jika f(x) = 3x² - 5 per x - 6 maka f(0) - f'(0) =
Matematika
Yunika11111
Pertanyaan
jika f(x) = 3x² - 5 per x - 6 maka f(0) - f'(0) =
2 Jawaban
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1. Jawaban Fauzieyah
f(x) = 3x^2 - 5 per x - 6
f'(x) = 6x per 1 = 6x
f(0) - f'(0)
= {(3(0)^2 - 5 per 0 - 6) - (6 x 0)}
= {(-5 per -6) - 0}
= 5 per 6
semoga membantu.. beri❤ dan jadikan sebagai jawaban terbaik ya... -
2. Jawaban arsetpopeye
f(x) = (3x^2 - 5)/(x - 6)
f(0) = (3.0^2 - 5)/(0 - 6) = -5/-6 = 5/6
f(x) = (3x^2 - 5)/(x - 6) = u/v
u = 3x^2 - 5 => u' = 6x
v = x - 6 => v' = 1
f'(x) = (u' v - v' u)/v^2
f'(x) = (6x (x - 6) - 1 (3x^2 - 5)) / (x - 6)^2
f'(0) = (6(0) (0 - 6) - 1(3(0)^2 - 5)) / (0 - 6)^2
f'(0) = (0(-6) - 1(0 - 5)) / (-6)^2
f'(0) = (0 - (-5)) / 36
f'(0) = 5/36
f(0) - f'(0) = 5/6 - 5/36 = (30 - 5)/36 = 25/36